x^2+12x+144=7+144

Solution for x^2+12x+144=7+144 equation:

x^2+12x+144=7+144

We move all terms to the left:

x^2+12x+144-(7+144)=0

We add all the numbers together, and all the variables

x^2+12x+144-151=0

We add all the numbers together, and all the variables

x^2+12x-7=0

a = 1; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·1·(-7)
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{43}}{2*1}=\frac{-12-2\sqrt{43}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{43}}{2*1}=\frac{-12+2\sqrt{43}}{2}
$